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	Comments on: Powers of Phi	</title>
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	<link>https://www.goldennumber.net/powers-of-phi/</link>
	<description>Golden Ratio, Phi, 1.618, and Fibonacci in Math, Nature, Art, Design, Beauty and the Face. One source with over 100 articles and latest findings.</description>
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	<item>
		<title>
		By: John Boyer		</title>
		<link>https://www.goldennumber.net/powers-of-phi/#comment-7554</link>

		<dc:creator><![CDATA[John Boyer]]></dc:creator>
		<pubDate>Sat, 14 Sep 2024 02:31:22 +0000</pubDate>
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					<description><![CDATA[There&#039;s an even easier way to find the nth power of phi.  I found it today.

phi^n = (phi)f(n) + f(n-1), where f(n) is the nth fibonacci number.

Once I found it, it was pretty easy to prove by induction.

And it seems that (1/phi)^n = &#124;f(n-1) - (1/phi)f(n)&#124;, but I haven&#039;t tried proving that one yet.]]></description>
			<content:encoded><![CDATA[<p>There&#8217;s an even easier way to find the nth power of phi.  I found it today.</p>
<p>phi^n = (phi)f(n) + f(n-1), where f(n) is the nth fibonacci number.</p>
<p>Once I found it, it was pretty easy to prove by induction.</p>
<p>And it seems that (1/phi)^n = |f(n-1) &#8211; (1/phi)f(n)|, but I haven&#8217;t tried proving that one yet.</p>
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		<title>
		By: petergrfstrm		</title>
		<link>https://www.goldennumber.net/powers-of-phi/#comment-7529</link>

		<dc:creator><![CDATA[petergrfstrm]]></dc:creator>
		<pubDate>Wed, 28 Aug 2024 12:07:46 +0000</pubDate>
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					<description><![CDATA[phi^înteger is approaching an integer exponentially as n increases
 it is a so called Pisot–Vijayaraghavan number
https://en.wikipedia.org/wiki/Pisot%E2%80%93Vijayaraghavan_number

n        phi^n                epsilon
34         12 752 043     -7,84e-8 
47  6 643 838 879    1,505e-10]]></description>
			<content:encoded><![CDATA[<p>phi^înteger is approaching an integer exponentially as n increases<br />
 it is a so called Pisot–Vijayaraghavan number<br />
<a href="https://en.wikipedia.org/wiki/Pisot%E2%80%93Vijayaraghavan_number" rel="nofollow ugc">https://en.wikipedia.org/wiki/Pisot%E2%80%93Vijayaraghavan_number</a></p>
<p>n        phi^n                epsilon<br />
34         12 752 043     -7,84e-8<br />
47  6 643 838 879    1,505e-10</p>
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		<title>
		By: Reid B		</title>
		<link>https://www.goldennumber.net/powers-of-phi/#comment-7280</link>

		<dc:creator><![CDATA[Reid B]]></dc:creator>
		<pubDate>Mon, 15 Jan 2024 01:00:06 +0000</pubDate>
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					<description><![CDATA[In reply to &lt;a href=&quot;https://www.goldennumber.net/powers-of-phi/#comment-2502&quot;&gt;Gary B Meisner&lt;/a&gt;.

Sqrt(2) + 1 also has this property, as does (3+sqrt(13))/2.  The thing I found in common with all of these numbers is that their continued fractions are all uniform, with the same number repeating infinitely.]]></description>
			<content:encoded><![CDATA[<p>In reply to <a href="https://www.goldennumber.net/powers-of-phi/#comment-2502">Gary B Meisner</a>.</p>
<p>Sqrt(2) + 1 also has this property, as does (3+sqrt(13))/2.  The thing I found in common with all of these numbers is that their continued fractions are all uniform, with the same number repeating infinitely.</p>
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		<title>
		By: Wasicki		</title>
		<link>https://www.goldennumber.net/powers-of-phi/#comment-7187</link>

		<dc:creator><![CDATA[Wasicki]]></dc:creator>
		<pubDate>Mon, 06 Nov 2023 03:02:43 +0000</pubDate>
		<guid isPermaLink="false">http://www.phisource.com/?p=525#comment-7187</guid>

					<description><![CDATA[Powers of phi can also be related to Lucas numbers through an infinite continued fraction:

phi^n = L(n) - (-1)^n/(L(n) - (-1)^n/(L(n) - (-1)^n/(L(n) - … )))

For example,

phi^3 = 4 + 1/(4 + 1/(4 + 1/(4 + … ))) = 4.236067977499789696409173668731…]]></description>
			<content:encoded><![CDATA[<p>Powers of phi can also be related to Lucas numbers through an infinite continued fraction:</p>
<p>phi^n = L(n) &#8211; (-1)^n/(L(n) &#8211; (-1)^n/(L(n) &#8211; (-1)^n/(L(n) &#8211; … )))</p>
<p>For example,</p>
<p>phi^3 = 4 + 1/(4 + 1/(4 + 1/(4 + … ))) = 4.236067977499789696409173668731…</p>
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		<title>
		By: Geoff Petrasek		</title>
		<link>https://www.goldennumber.net/powers-of-phi/#comment-6745</link>

		<dc:creator><![CDATA[Geoff Petrasek]]></dc:creator>
		<pubDate>Wed, 15 Feb 2023 18:41:15 +0000</pubDate>
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					<description><![CDATA[In reply to &lt;a href=&quot;https://www.goldennumber.net/powers-of-phi/#comment-720&quot;&gt;Heyhey1D&lt;/a&gt;.

Phi is found in the power of the sun. It represents natures response to energy which is to maximize its use thru genetic adaptation. For example, the spacing of leaves, and seeds to maximize growth. Phi is a sacred gift from God.]]></description>
			<content:encoded><![CDATA[<p>In reply to <a href="https://www.goldennumber.net/powers-of-phi/#comment-720">Heyhey1D</a>.</p>
<p>Phi is found in the power of the sun. It represents natures response to energy which is to maximize its use thru genetic adaptation. For example, the spacing of leaves, and seeds to maximize growth. Phi is a sacred gift from God.</p>
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		<title>
		By: Neal		</title>
		<link>https://www.goldennumber.net/powers-of-phi/#comment-6639</link>

		<dc:creator><![CDATA[Neal]]></dc:creator>
		<pubDate>Thu, 15 Dec 2022 21:09:19 +0000</pubDate>
		<guid isPermaLink="false">http://www.phisource.com/?p=525#comment-6639</guid>

					<description><![CDATA[Playing around in MS Mathematics I found that

Phi^(n) + Phi^(n+1) = Phi^(n+2)

Is just one instance of the more general 

Phi^(n/a) + Phi^((n+a)/a) = Phi^((n+2a)/a)
Where a does not equal 0 because zero root is undefined. 

The top example is a=1. 

I&#039;ve searched for other mentions of this online, but could not find any.  My searches have led me here.]]></description>
			<content:encoded><![CDATA[<p>Playing around in MS Mathematics I found that</p>
<p>Phi^(n) + Phi^(n+1) = Phi^(n+2)</p>
<p>Is just one instance of the more general </p>
<p>Phi^(n/a) + Phi^((n+a)/a) = Phi^((n+2a)/a)<br />
Where a does not equal 0 because zero root is undefined. </p>
<p>The top example is a=1. </p>
<p>I&#8217;ve searched for other mentions of this online, but could not find any.  My searches have led me here.</p>
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		<item>
		<title>
		By: Ramsey		</title>
		<link>https://www.goldennumber.net/powers-of-phi/#comment-6572</link>

		<dc:creator><![CDATA[Ramsey]]></dc:creator>
		<pubDate>Wed, 05 Oct 2022 15:32:09 +0000</pubDate>
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					<description><![CDATA[where multiplication and addition of exponents of Phi are the same, which is a marveollous thing.]]></description>
			<content:encoded><![CDATA[<p>where multiplication and addition of exponents of Phi are the same, which is a marveollous thing.</p>
]]></content:encoded>
		
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		<title>
		By: *Secret*		</title>
		<link>https://www.goldennumber.net/powers-of-phi/#comment-6065</link>

		<dc:creator><![CDATA[*Secret*]]></dc:creator>
		<pubDate>Mon, 14 Jun 2021 12:14:35 +0000</pubDate>
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					<description><![CDATA[The second equation is right]]></description>
			<content:encoded><![CDATA[<p>The second equation is right</p>
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		<item>
		<title>
		By: Dav Jons		</title>
		<link>https://www.goldennumber.net/powers-of-phi/#comment-5761</link>

		<dc:creator><![CDATA[Dav Jons]]></dc:creator>
		<pubDate>Mon, 12 Apr 2021 09:17:34 +0000</pubDate>
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					<description><![CDATA[Oh! That is an interesting topic I also have a query about this topic. In this way, the ratio of terms of the Fibonacci sequence approaches phi. The sequence of the element&#039;s approach (phi^n)/sqrt(5) on the way of sequence approaches a geometric. One could take the general formula for the sum of a geometric series to at least approximate the sums you began all, but it’d take an impartially large &#039;n&#039; to get good results. I just need to found this type of blog and also gives a lot of help in such &lt;a href=&quot;https://mycalcu.com/fraction-calculator&quot; rel=&quot;nofollow ugc&quot;&gt;solve fractive issue&lt;/a&gt;
, and I’m really enjoying it!.]]></description>
			<content:encoded><![CDATA[<p>Oh! That is an interesting topic I also have a query about this topic. In this way, the ratio of terms of the Fibonacci sequence approaches phi. The sequence of the element&#8217;s approach (phi^n)/sqrt(5) on the way of sequence approaches a geometric. One could take the general formula for the sum of a geometric series to at least approximate the sums you began all, but it’d take an impartially large &#8216;n&#8217; to get good results. I just need to found this type of blog and also gives a lot of help in such <a href="https://mycalcu.com/fraction-calculator" rel="nofollow ugc">solve fractive issue</a><br />
, and I’m really enjoying it!.</p>
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		<title>
		By: M.D.		</title>
		<link>https://www.goldennumber.net/powers-of-phi/#comment-5478</link>

		<dc:creator><![CDATA[M.D.]]></dc:creator>
		<pubDate>Sun, 20 Sep 2020 16:13:54 +0000</pubDate>
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					<description><![CDATA[Roots of Lucas numbers tend towards Φ
199^(1/10)=1,61803....]]></description>
			<content:encoded><![CDATA[<p>Roots of Lucas numbers tend towards Φ<br />
199^(1/10)=1,61803&#8230;.</p>
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