You can have two different infinities if put in separate but parallel spaces.

The only PROOF of pi=3.14159.. being wrong is with physical measurement.

Another demonstration i just made , signup on this site and comment !

https://mathforums.com/t/debate-topic-%CF%80-%E2%89%A0-3-14159-%CF%80-4-%E2%88%9A%CE%A6.351920/page-107#post-699307

I was looking at your work but I can’t see where is your proof that π is a function of the Golden Ratio.
Could you show me where is it?

I am sorry but i can’t
i drop the png or jpg image and nothing happened, nor is there a button for uploading.

This is the same picture as you can see i my post on the forum.
Give me your adr email or the moderator can send it to me and i will send the picture to you.

https://mathforums.com/t/debate-topic-%CF%80-%E2%89%A0-3-14159-%CF%80-4-%E2%88%9A%CE%A6.351920/post-688195

The same as A triangle on figure 2 here too :

http://www.proofpi.com/pi-v-pi.php

Could you upload a diagram?
Thanks!

Like i said i suppose that squaring the circle is possible.
So we have a circle with a radius = 1, so with circumference = 2pi = perimeter of the square
Each side of the square = 2π/4 = π/2
Then we have a right triangle with Hypotenuse = radius of the circle = 1
Height of the triangle = half the side of the square = 2π/8 = π/4
Base of the triangle = b

So Pythagorean theorem give 1 = (π/4)² + b²

By building 1 other triangle 4/π bigger and another 4/π bigger again we get 3 equations.
With π = 4/√ɸ and b = (π/4)² this solve the 3 equations.

And then I ask what other values can solve these 3 equations with 3 criteria :

– π must begin by 3.14, near Archimedes constant as the measurements show.
– There must be a simple formula for b and π.
– The squaring of the circle should be easy to draw with a compass and a ruler.

“…I did a demonstration here :
https://mathforums.com/t/debate-topic-%CF%80-%E2%89%A0-3-14159-%CF%80-4-%E2%88%9A%CE%A6.351920/post-689351”

I can’t see how do you justify the hypotenuse being 1 and the leg of the triangle being π/4.
This would be the demonstration, in fact.

Please open an account in that forum and publish your demonstration in the topic.
Your video was already discussed in that topic. (you can see it with the link i provided).
Thanks

“……here is the video : https://www.youtube.com/watch?v=ccxVW2MIbxA”

Well, I must confess. This is in fact my work.
My name is C. Baikouzis.

They are a similar demonstration video as you did and was put on this forum and i commented on it.

https://mathforums.com/t/debate-topic-%CF%80-%E2%89%A0-3-14159-%CF%80-4-%E2%88%9A%CE%A6.351920/post-688571

And another with a premise : “there is always one Right Triangle with shorts sides x“ and x^2“. This is known.”

here is the video : https://www.youtube.com/watch?v=ccxVW2MIbxA

I did a demonstration here :
https://mathforums.com/t/debate-topic-%CF%80-%E2%89%A0-3-14159-%CF%80-4-%E2%88%9A%CE%A6.351920/post-689351

I suggest you publish your findings on this topic of this forum.