Phi, Φ, 1.618…, has two properties that make it unique among all numbers.
- If you square Phi, you get a number exactly 1 greater than itself: 2.618…, or
Φ² = Φ + 1.
- If you divide Phi into 1 to get its reciprocal, you get a number exactly 1 less than itself: 0.618…, or
1 / Φ = Φ – 1.
These relationships are derived from the dividing a line at its golden section point, the point at which the ratio of the line (A) to the larger section (B) is the same as the ratio of the larger section (B) to the smaller section (C).
This relationship is expressed mathematically as:
A = B + C, and
A / B = B / C.
Solving for A, which on both sides give us this:
B + C = B²/C
Let’s say that C is 1 so we can determine the relative dimensions of the line segments. Now we simply have this:
B + 1 = B²
This can be rearranged as:
B² – B – 1 = 0
Note the various ways that this equation can be rearranged to express the relationship of the line segments, and also Phi’s unique properties:
B2 = B + 1
1 / B = B – 1
B2 – B1 – B0 = 0
Note: Bx means n raised to the x power. Some browsers may not display exponents as superscripts or raised characters.
Now we have a formula that can be solved using the Quadratic formula, the solution to the equation is (1 plus or minus the square root of 5) divided by 2:
( 1 + √5 ) / 2 = 1.6180339… = Φ
( 1 – √5 ) / 2 = -0.6180339… = -Φ
The reciprocal of Phi (denoted with an upper case P), is known often as by phi (spelled with a lower case p).
Phi, curiously, can also be expressed all in fives as:
5 ^ .5 * .5 + .5 = Φ
This provides a great, simple way to compute phi on a calculator or spreadsheet!
Determining the nth number of the Fibonacci series
You can use phi to compute the nth number in the Fibonacci series (fn):
fn = Φ n / 5½
As an example, the 40th number in the Fibonacci series is 102,334,155, which can be computed as:
f40 = Φ 40 / 5½ = 102,334,155
This method actually provides an estimate which always rounds to the correct Fibonacci number.
You can compute any number of the Fibonacci series (fn) exactly with a little more work:
fn = [ Φ n – (-Φ)-n ] / (2Φ-1)
Note: 2Φ-1 = 5½= The square root of 5
Determining Phi with Trigonometry and Limits
Phi can be related to e, the base of natural logs,
through the inverse hyperbolic sine function:
Φ = e ^ asinh(.5)
It can be expressed as a limit:
Other unusual phi relationships
There are many unusual relationships in the Fibonacci series. For example, for any three numbers in the series Φ(n-1), Φ(n) and Φ(n+1), the following relationship exists:
Φ(n-1) * Φ(n+1) = Φ(n)2 – (-1)n
( e.g., 3*8 = 52-1 or 5*13=82+1 )
Every nth Fibonacci number is a multiple of Phi(n),
where Phi(n) is the nth number of the Fibonacci sequence.
Given 0, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377, 610, 987, 1597, 2584, 4181, 6765
(Every 4th number, e.g., 3, 21, 144 and 987, are all multiples of Phi(4), which is 3)
(Every 5th number, e.g., 5, 55, 610, and 6765, are all multiples of Phi(5), which is 5)
The first perfect square in the Fibonacci series, 144,
is number 12 in the series and its square root is 12!
0, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144
or, if not starting with 0:
1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144